Antimonypentachloride Dissociation Constant

Define

as the fraction of

that reacts. At 238 °C and 1 atm pressure,

= 0.718 for the reaction

(g)

(g) +

(g)
Starting with pure

, calculate

for this reaction.

Here is some help in thinking about this problem. When one mole of

(g) decomposes,

moles of

and

moles of

are ``created''. As a result the total number of moles of gas would now be

i.e.,

, so the mole fraction of each component would be:

Therefore, converting the mole fractions into partial pressures we would have

where we have made P=1 (atm) so it is invisible. Now we solve for knowing .
End of helpful hint.

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. E{ }

Carl W. David
Department of Chemsitry
University of Connecticut
Storrs, Connecticut 06269-4060
(860)486-3217
david@uconnvm.uconn.edu