Angular Momentum of Trial Eigenfunction

The operator for in spherical polar coördinates is

so, for an eigenfunction of this operator, one would have:

What is the value associated with the function ?

Choose your answer in scientific notation, i.e., ± x.yzE{± ab}, and then press the 'Submit the above answer' button (below).

. E{ }



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Carl W. David
Department of Chemsitry
University of Connecticut
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david@uconnvm.uconn.edu