Figure 1: The Carnot Cycle
For a reversible Carnot engine operating between and , whose working fluid is two moles of a monatomic ideal gas, if is exactly one-half , obtain the value of , the change in energy, in going from point A to Point C. Point A in this Carnot cycle, according to our usage, is the `corner' where the volume is smallest at . Point B is on the same isotherm. Point C is connected to Point B by a reversible adiabatic expansion and lies on the isotherm.. Give your answer in calories. Use R = 1.987 cal/(mol °K).
You can use two asterisks, `**', or a caret, `^', to indicate powers, i.e., v^2 and v**2 both mean v squared.
Query, is the above formula correct?
Carl W. David